Structural Analysis Fundamentals / Engineering materials
The tensile test and the stress–strain curve
Where E, yield, ultimate strength and ductility actually come from.
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Read the lesson register and outstanding review notesWhy this matters
A tensile test measures load and extension on a prepared specimen. It provides material data such as elastic modulus, yield or proof stress, tensile strength and elongation. These results need appropriate test conditions and do not, on their own, establish member capacity.
By the end of this lesson you should be able to
- Describe how a tensile test is carried out and what is measured
- Identify the regions of a stress–strain curve and what each one means
- Calculate E, yield stress, ultimate stress and ductility from test data
- Explain why the nominal curve falls after the ultimate point
What you should already know
- Direct stress and strain (Module 7)
- Hooke's law and Young's modulus (Module 7)
A tensile test loads a specimen of measured initial area A₀ and gauge length L₀, recording force and gauge extension. Nominal stress is P/A₀ and nominal strain is δ/L₀.
Normalising by the initial dimensions allows specimens to be compared under equivalent test conditions. Temperature, loading rate, material orientation and specimen geometry can still affect the results, especially after localisation.
A typical mild-steel tensile curve begins with a linear elastic region whose slope is E. The proportional limit marks the end of linearity; the elastic limit concerns recovery after unloading.
Yielding may produce a plateau, followed by strain hardening as further plastic deformation requires higher stress. Not every steel has a distinct plateau.
At the maximum nominal stress, deformation begins to localise into a neck. The specimen then carries a decreasing load as its section reduces. Damage can develop before fracture, so neither continuing hardening nor a visible warning in a structural member should be assumed from this curve alone.
Predict first
During necking, the current area decreases faster proportionally than the load. What happens to the average true axial stress P/A?
Brittle materials have limited plastic deformation before fracture. Cracking and other observations may occur, but should not be relied on to provide warning.
Materials without a distinct yield plateau can be characterised by proof stress. For 0.2% proof stress, draw a line parallel to the initial elastic slope at an offset strain of 0.002. Its intersection with the measured curve defines the value. With elastic unloading at that slope, the corresponding permanent strain is 0.002.
Ductility is measured after the test, from the broken halves fitted back together, and is reported two ways:
- Percentage elongation = (Lf − L₀)/L₀ × 100
- Percentage reduction in area = (A₀ − Af)/A₀ × 100
Elongation depends on the gauge length used, because most of the extension is concentrated in the neck — so a quoted elongation is meaningless unless the gauge length is quoted with it. Reduction in area does not have that problem, but is harder to measure.
Ductility is not a strength. It buys you something different and arguably more valuable: warning, and the ability of a structure to redistribute load away from an overstressed region instead of tearing there.
Try it
The tensile test, all the way to fracture
A real stress–strain curve, not the elastic line. Pull the specimen and watch it pass yield, harden, neck and break — and watch what unloading does at each stage.
Specimen
Curves
0.2% proof construction
- Modulus E
- 205 GPa
- Yield (upper / lower)
- 285 / 275 N/mm²
- Ultimate stress
- 430 N/mm²
- Elongation at fracture
- 28.0 %
- Reduction of area
- 60 %
- Ductile
- yes
- Toughness (area under curve)
- 105.2 MJ/m³
- Resilience (elastic only)
- 0.20 MJ/m³
- — at this pull —
- 11.20 % strain
- Elastic recovery on unloading
- 0.190 %
- Permanent set
- 11.01 %
- Necking
- no
Things worth trying
- Start on mild steel and pull slowly. Elastic behaviour ends at 0.14% strain — half a percent of the way along this slider. Everything else on the curve, all 28% of it, is permanent deformation. That ratio is the single most surprising thing about the diagram.
- Stop just past yield. The stress goes FLAT: the material is flowing at constant load. That plateau is why a mild-steel member gives warning before it fails, and it is the single most valuable property in the diagram.
- Watch the dashed unloading line appear once you pass yield. It runs parallel to the elastic line, NOT back down the curve — the strain splits into a part that comes back and a part that does not.
- Pull to 100%. Engineering stress FALLS after the peak. It looks as though the material is getting weaker, and that reading is wrong.
- Now switch on the true-stress curve. It keeps rising all the way to fracture. Engineering stress divides the load by the ORIGINAL area while the specimen is thinning at the neck; true stress divides by the actual one. The bar is getting smaller, not weaker.
- Switch to cast iron. It fractures at 0.7% strain, barely past elastic, with no warning at all — and its toughness is under 1 MJ/m³ against mild steel's 100-odd. Strength is the HEIGHT of this curve; toughness is its AREA.
- Switch to high-strength steel and turn on the 0.2% construction. There is no plateau, so there is no stress at which yielding visibly starts — the offset line DEFINES one. Turn it on for mild steel and the readout says to use the real yield instead.
- Try the construction on cast iron. The line does meet the curve, and the answer is still refused: a proof stress presumes a plastic region worth describing, and this material has none.
- Compare the two steels. Twice the strength buys half the ductility, and the reserve between yield and ultimate falls from 155 to 100 N/mm². Strength is never free.
Worked example
Reading a tensile test record
Given
- Round specimen, original diameter d₀ = 12.0 mm
- Original gauge length L₀ = 60.0 mm
- Extension measured at a load of 20.0 kN, still within the elastic region
- E = 205 000 N/mm² for this steel
- Load at yield = 33.9 kN; maximum load = 48.0 kN
- After fracture: gauge length 74.4 mm, minimum diameter 8.40 mm
Find
The original area, yield and ultimate stresses, the elastic extension at 20 kN, and the two ductility measures.
Practice
A round tensile specimen of original diameter 10.0 mm yields at a load of 24.0 kN. What is the yield stress, in N/mm²?
Practice
The same specimen had an original gauge length of 50.0 mm. After fracture the two halves fitted together measure 61.5 mm across the gauge marks. What is the percentage elongation?
Practice
An aluminium alloy has no defined yield point, so its strength is quoted as a 0.2% proof stress of 480 N/mm². If a specimen is loaded to exactly that stress and then fully unloaded, what permanent strain remains?
It is worth naming the classification the tensile test implies, because it drives structural choices more than any single strength figure.
Ductile materials — structural steel, aluminium alloys, copper — have a large plastic region. They deform visibly before failing, they absorb a great deal of energy, and they redistribute load away from an overstressed region. Every method in this course that relies on redistribution assumes ductility.
Brittle materials — cast iron, glass, concrete in tension, most ceramics — have almost no plastic region. They fail at small strain with little warning and absorb little energy. Their tensile strength is also highly variable, because it is governed by the largest flaw present rather than by the bulk material.
Materials that behave differently in tension and compression. Concrete is the structural example: strong in compression, weak and unreliable in tension. That single asymmetry is the reason reinforced concrete exists, and the reason cracked-section analysis discards the concrete below the neutral axis.
Time-dependent materials — timber, polymers, and concrete over years — deform appreciably under sustained load. Their short-term test results do not describe their long-term behaviour.
The strain-hardening region seen after the yield plateau is what gives ductile materials their reserve. Dislocations become tangled and obstruct one another, so more stress is required to continue deforming. The ratio of ultimate to yield stress is a rough measure of how much reserve there is: around 1.4 for a typical mild steel, and closer to 1.1 for a high-strength steel — which is one reason very high-strength steels are treated more cautiously.
Practice
A mild steel has a yield stress of 275 N/mm² and an ultimate tensile strength of 410 N/mm². What is the ratio of ultimate to yield stress?
Check yourself
Which property makes a material suitable for plastic design and moment redistribution?
Summary
- Nominal stress and strain use the original dimensions, which makes the curve a material property
- E is the slope of the elastic region and is measured nowhere else on the curve
- The nominal curve can fall as deformation localises and the section reduces; true stress needs the current area and a suitable local interpretation
- Proof stress is a convention for materials with no yield plateau: 0.2% offset leaves 0.2% permanent strain
- Ductility permits plastic deformation; structural warning and redistribution also depend on the failure mode and detailing